-24i^2+55i-25=0

Solution for -24i^2+55i-25=0 equation:

-24i^2+55i-25=0

a = -24; b = 55; c = -25;
Δ = b2-4ac
Δ = 552-4·(-24)·(-25)
Δ = 625
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$i_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$i_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{625}=25$
$i_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(55)-25}{2*-24}=\frac{-80}{-48}
=1+2/3
$
$i_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(55)+25}{2*-24}=\frac{-30}{-48}
=5/8
$